How many milliliters of a 2,000.0 mg/dL glucose stock solution are needed to prepare 100.0 mL of a 150.0 mg/dL glucose working standard?

To determine how many milliliters of a 2,000.0 mg/dL glucose stock solution are required to prepare 100.0 mL of a 150.0 mg/dL glucose working standard, you can use the dilution equation, which is based on the principle of conservation of mass in dilutions. The equation can be represented as:

C1V1 = C2V2

In this equation:

• C1 is the concentration of the stock solution (2,000.0 mg/dL).

• V1 is the volume of the stock solution we need to find.

• C2 is the concentration of the working solution (150.0 mg/dL).

• V2 is the final volume of the working solution (100.0 mL).

Plugging in the known values into the equation gives:

(2,000.0 mg/dL) * V1 = (150.0 mg/dL) * (100.0 mL)

To find V1, rearrange the equation:

V1 = (150.0 mg/dL * 100.0 mL) / (2,000.0 mg/dL)

Calculating the values:

V1 = (15,000 mg